Answer:
![\text{p}-4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/odpkzcw3ovb0rgc8j5bd92w4p0ghd02kfc.png)
Explanation:
Given: If Sergio has
paintings in his art collection and he and other collectors donate a total of
paintings each of the
will donate the same number of paintings.
To Find: Number of paintings Sergio have left.
Solution:
Number of paintings Sergio initially have
![=\text{p}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/o5j483odyfoykx5cw3usbr79v0y9xe4v1c.png)
Total number of paintings donated
![=48](https://img.qammunity.org/2019/formulas/mathematics/middle-school/8tzjd1xv46wejaz24gztlnnxqxnte088qd.png)
Total number of Collectors
![=12](https://img.qammunity.org/2019/formulas/mathematics/middle-school/dcau9vh747kw9nkk4g9i9c6b49xidqy0o1.png)
As each collector donate the same number of painting
Paintings donated by each collector
![=\frac{\text{Total number of paintings}}{\text{Number of collectors}}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/fvp7k6qtuioh9bffjqa0n1klfbrd23wpzs.png)
![(48)/(12)=4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/wu6cx1ss17v1mlpewbitjm4ql1a87gmizw.png)
Therefore Paintings donated by Sergio
![=4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/vzl622mktt80r0qqqkxhkxbzsgtn0sfnmp.png)
Total number of paintings Sergio have left
![=\text{Number of paintings Sergio have}-\text{total number of paintings Sergio donated}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/yp9krcnywi8or8qt0q7982ob3wy4nbdu1t.png)
![=\text{p}-4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/ioutrsu7xwpb1j0tbngmhf5eiu0jn1smf4.png)
Hence Sergio have left
Paintings