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What would be the final volume (in mL) of the aqueous potassium fluoride which was prepared by dissolving 8.0 g of potassium fluoride in an appropriate volume of water to give a 0.89 M aqueous solution?

User Tmilar
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1 Answer

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n=m/M

8.0g÷58.10g/mol=0.14mol

V=n/c

0.14mol÷0.89M=0.16L=1.6×10²mL

User RVM
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