Question

What would be the final volume (in mL) of the aqueous potassium fluoride which was prepared by dissolving 8.0 g of potassium fluoride in an appropriate volume of water to give a 0.89 M aqueous solution?

Answer 1

n=m/M

8.0g÷58.10g/mol=0.14mol

V=n/c

0.14mol÷0.89M=0.16L=1.6×10²mL