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Lash asked Dec 3, 2023

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17 votes

Lash asked Dec 3, 2023

by Lash

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14 votes

Part (a)

f(0)=-0^3+4(0)^2-2(0)+2=2

Part (b)

$f(3)=-3^3+4(3)^2-2(3)+2 \\ \\ =-27+36-6+2 \\ \\ =9-4 \\ \\ =5$

Part (c)

$f(-2)=-(-2)^3+4(-2)^2-2(-2)+2 \\ \\ =8+16+4+2 \\ \\ =30$

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