Question

Can someone explain what to do and how to set up

Answer 1

We know that According to Law of Sines :

`\clubsuit`
`(SinA)/(a) = (SinB)/(b) = (SinC)/(c)`

Where A - B - C are Angles of the Triangle and a - b - c are Opposite Sides corresponding to those Angles A - B - C

We need to find the length of Path-2 whose Opposite Angle is 45°

We need to find the Angle Opposite to 300 m length to solve the problem

Angle Opposite to 300 m Length = 180° - (45° + 105°) = 30°

⇒
`(Sin45)/(Length\;of\;Path-2) = (Sin30)/(300)`

⇒
`(1)/(√(2)(Length\;of\;Path-2)) = (1)/(600)`

⇒
`Length\;of\;Path-2 = (600)/(√(2)) = 424\;m`

Option D is the Answer