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How do you work out question 1a?

How do you work out question 1a?-example-1
User Kiritsuku
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1 Answer

4 votes

Answer:

-125 kJ

Explanation:

You calculate the energy required to break all the bonds in the reactants. Then you subtract the energy to break all the bonds in the products.

H₂C=CH₂ + H₂ ⟶ H₃C-CH₃

Bonds: 4C-H + 1C=C 1H-H 6C-H + 1C-C

D/kJ·mol⁻¹: 413 612 436 413 347

The formula relating ΔHrxn and bond dissociation energies (D) is

ΔHrxn = Σ(Dreactants) – Σ(Dproducts)

(Note: This is an exception to the rule. All other thermochemical reactions are “products – reactants”. With bond energies, it’s “reactants – products”. The reason comes from the way we define bond energies.)

For the reactants:

Σ(Dreactants) = 4 × 413 + 1 × 612 + 1 × 436 = 2700 kJ

For the products:

Σ(Dproducts) = 6 × 413 + 1 × 347 = 2825 kJ

For the system :

ΔHrxn = 2700 - 2825 = -125 kJ

User Rcl
by
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