Question

1. the position of a particles moving on a straight line is given by X =12 + 18t + 9t^2meter

(a) find the instantaneous veloctiy at
t=5s [dx/dt=v]

Answer 1

v = 108 m/s.

Step-by-step explanation:

Given that,

The position of a particle moving on a straight line is given by :

`X =12 + 18t + 9t^2`

We need to find the instantaneous velocity at t=5s.

Velocity,
`v=(dX)/(dt)`

So,

`v=(d(12 + 18t + 9t^2))/(dt)\\\\=18+18t`

Instantaneous velocity at t = 5 s will be :

v = 18+18t

v = 18+18(5)

= 18 + 90

= 108 m/s

So, the instantaneous veloctiy at t=5s is 108 m/s.