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F(x+1)+f(x+2)=2x+3; f(x)=?

1 Answer

12 votes

Answer:


F=(-xf+f+2x)/(x+1);\quad \:x\\e \:-1

Explanation:


1. \mathrm{Subtract\:}f\left(x+2\right)\mathrm{\:from\:both\:sides}\\ F\left(x+1\right)+f\left(x+2\right)-f\left(x+2\right)=2x+3f-f\left(x+2\right)


2. \mathrm{Simplify}\\ F\left(x+1\right)=-xf+f+2x\\


3. \mathrm{Divide\:both\:sides\:by\:}x+1;\quad \:x\\e \:-1\\ (F\left(x+1\right))/(x+1)=-(xf)/(x+1)+(f)/(x+1)+(2x)/(x+1);\quad \:x\\e \:-1


4. \mathrm{Simplify}\\ F=(-xf+f+2x)/(x+1);\quad \:x\\e \:-1

Final Answer:
F=(-xf+f+2x)/(x+1);\quad \:x\\e \:-1

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