Question

If (x^100+2x^99+k)is divisible by (x+1) then the value of k is

please answer :)

15 points

Answer 1

k = 1

Explanation:

since the polynomial is divisible by (x + 1) then x = - 1 is a root and will make the polynomial equal to zero.

substitute x = - 1 and equate to zero

`(-1)^(100)` + 2
`(-1)^(99)` + k = 0 , that is

1 + 2(- 1) + k = 0

1 - 2 + k = 0

- 1 + k = 0 ( add 1 to both sides )

k = 1