Write the expression in standard form. 2/(2-15i) a. 4/229 - 30/229i b. -4/229 + 30/229i c. -4/229 - 30/229i d. 4/229 +30/229i

Question

asked Jun 2, 2019 8.2k views

1 Answer

asked Nov 7, 2024 199k views

Memememe asked Nov 7, 2024

7.4k points

1 answer

4 votes

199k views

asked Jul 16, 2024 179k views

JacekK asked Jul 16, 2024

8.8k points

2 answers

0 votes

179k views

asked Nov 4, 2024 85.0k views

RKN asked Nov 4, 2024

by RKN

8.8k points

1 answer

4 votes

85.0k views

Dawood Awan · Answer 1 · 2019-06-07T07:28:08+0000

d. 4/229 +30/229i

Multiply numerator and denominator by the conjuate of the denominator, then simplify.

$(2)/(2-15i)=(2)/((2-15i))\cdot((2+15i))/((2+15i))=(4+30i)/(2^2-(15i)^2)\\\\=(4+30i)/(4+225)=(4)/(229)+(30)/(229)i$