The points are (0,2), (1,4), (2,8)
Notice that as x increases from 0 to 1 (a change of +1), y increases from 2 to 4 (a change of +2). If this were a linear function, the slope would be 4.
As x increases from 1 to 2 (a change of +1), y increases from 2 to 4 (a change of +2). If this were a linear function, the slope would be 2.
But as x increases from 2 to 3 (a change of +1), y increases from 4 to 8 (a change of +8). If this were a linear function, the slope would be 4.
Thus, the slope of the graph is not uniform and the function therefore cannot be linear. We reject f(x) = 4x and f(x) = 2x + 2.
Now let's check out f(x) = 2(2)^x: f(0) = 2; f(1) = 4; f(2) = 8. This agrees with the data.
Let's also check out f(x) = x^2+2. f(0) = 2; f(1) = 3; f(2) = 6. This definitely does not match the given data.
The correct answer is the first one: f(x) = 2(2)^x.