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A 800N student does a handstand with both hands at an angle of 15 degrees from the vertical what is the force on each hand

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here we can say that net force on the student vertically upwards will be counter balance by his weight downwards

Let net force F is exerted by each hand

so here we will have


2Fcos15 = W


2F cos15 = 800


F = (800)/(2 cos15)


F = 414.1 N

so the force exerted by each hand will be 414.1 N

User James Van Dyke
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