Question

How many kj of heat are needed to completely vaporize 3.30 moles of h2o? the heat of vaporization for water at the boiling point is?

Answer 1

The heat of vaporization for water at the boiling point is 40.6 kJ/mole

Q = ( moles of water ) ( molar latent enthalpy of water or heat of vaporization of water )

Q = 3.30 moles X 40.6 kJ/mole = 134 kJ