Question

Ammonia (nh3(g), hf = –46.19 kj/mol) reacts with hydrogen chloride (hcl(g), hf = –92.30 kj/mol) to form ammonium chloride (nh4cl(s), hf = –314.4 kj/mol) according to this equation: nh3(g) + hcl(g) nh4cl(s) what is hrxn for this reaction?

Answer 1

Answer:-175.9

Step-by-step explanation:

trust

Answer 2

Answer: The
`\Delta H_(rxn)` for the given chemical reaction is -175.51 kJ/mol

Explanation: Enthalpy change of the reaction is defined as the amount of heat released or absorbed in a given chemical reaction.

Mathematically,

`\Delta H_(rxn)=\Delta H_f_((products))-\Delta H_f_((reactants))`

We are given a chemical reaction. The reaction follows:

`NH_3(g)+HCl(g)\rightarrow NH_4Cl(s)`

`H_f_((NH_3))=-46.19kJ/mol`

`H_f_((HCl))=-92.30kJ/mol`

`H_f_((NH_4Cl))=-314.4kJ/mol`

Enthalpy change for the reaction of he given chemical reaction is given by:

`\Delta H_(rxn)=H_f_((NH_4Cl))-(H_f_((NH_3))+H_f_((HCl)))`

Putting the values in above equation, we get

`\Delta H_(rxn)=-314.4-(-92.30-46.19)kJ/mol`

`\Delta H_(rxn)=-175.51kJ/mol`