Question

How much would the boiling point of water increase if 4 mol of sugar were added to 1 kg of water (Kb = 0.51°C/(mol/kg) for water and i = 1 for sugar)?

Answer 1

2.04°C

Step-by-step explanation:

Answer 2

Answer : The boiling point of water increases,
`2.04^oC`

Solution : Given,

Moles of solute (sugar) = 4 moles

Mass of solvent (water) = 1 Kg

`K_b=0.51Kg^oC/mole`

i = 1 for sugar

Formula used :

`\Delta T_b=i* K_b* m\\\Delta T_b=i* K_b* (n_(solute))/(w_(solvent))`

Where,

`\Delta T_b` = elevation in boiling point

`K_b` = elevation constant

m = molality

`n_(solute)` = moles of solute (sugar)

`w_(solvent)` = mass of solvent (water)

i = van't Hoff factor

Now put all the given values in this formula, we get the elevation in boiling point of water.

`\Delta T_b=(1)* (0.51Kg^oC/mole)* (4moles)/(1Kg)=2.046^oC`

Therefore, the elevation in boiling point of water is
`2.04^oC`