Answer:
a) √2
b) √(5a)
c) √3
d) -√2
e) -√(3x)
Explanation:
This problem set makes use of the relation ...
... a√b = √(a²b)
a) (1/3)√18 = √(18·(1/3)²) = √(18/9) = √2
b) 5√(a/5) = √(25a/5) = √(5a)
c) 2√(3/4) = √(4·3/4) = √3
d) -10√0.02 = -√(100·0.02) = -√2
e) -(1/2)√(12x) = -√(12x/4) = -√(3x)
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