Question

Find an equation of the line that has the given slope and contains the given point. m=7/3 (1,6)

Answer 1

The point-slope form:

`y-y_1=m(x-x_1)`

We have the point (1, 6) and the slope m = 7/3. Substitute:

`y-6=(7)/(3)(x-1)` use distributive property

`y-6=(7)/(3)x-(7)/(3)` add 6 to both sides

`y=(7)/(3)x+(11)/(3)` multiply both sides by 3

`3y=7x+11` subtract 7x from both sides

`-7x+3y=11` change the signs

`7x-3y=-11`

Answer:

point-slope form:
`y-6=(7)/(3)(x-1)`

slope-intercept form:
`y=(7)/(3)x+(11)/(3)`

standard form:
`7x-3y=-11`