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A hemispherical tank is filled with water and has a diameter of 14 feet. If water

weighs 62.4 pounds per cubic foot, what is the total weight of the water in a full tank,
to the nearest pound?

User Sunysen
by
5.1k points

1 Answer

3 votes

Answer:


44,826.72\ \text{pounds}

Explanation:

Given that,

The diameter of a hemispherical tank= 14 feet

Radius, r = 7 feet

water

Water weighs 62.4 pounds per cubic foot.

We need to find the total weight of the water in a full tank to the nearest pound.

The volume of the hemisphere is given by :


V=(2)/(3)\pi r^3\\\\V=(2)/(3)\pi * (7)^3\\\\V=718.377\ \text{feet}^3

If water weighs 62.4 pounds per cubic foot, it means


V=718.377* 62.4\\\\V=44,826.72\ \text{pounds}

So, the total weight of the water is
44,826.72\ \text{pounds}.

User Olivier Croisier
by
4.7k points