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6 votes
Please help 30 points

I graphed the seamos out already and the question are in a separate picture

Please help 30 points I graphed the seamos out already and the question are in a separate-example-1
User Nikkorian
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1 Answer

6 votes

Answer: On interval f(x) is increasing =
( -\infty, -2)

On interval f(x) is decreasing =
( -\infty, -2)

Explanation:

The given function:
f(x)=-(x+2)^2+4

The graph of the function is attached below

In graph , function is increasing till point (-2,4) or x=-2 and then it is decreasing.

So f(x) is increasing in
( -\infty, -2) and decreasing in
(-2, \infty)

So, On interval f(x) is increasing =
( -\infty, -2)

On interval f(x) is decreasing =
( -\infty, -2)

Please help 30 points I graphed the seamos out already and the question are in a separate-example-1
User Pieter Van Wyk
by
4.9k points