111k views
6 votes
Please answer this questions step by step​

Please answer this questions step by step​-example-1

1 Answer

2 votes

Answer:

(a) When a = 4 and b = -5, a² + b² - a·b = 61

(b) When a = 4 and b = -5, a³·b + a·b² = -220

(c)
When \ a = 4 \ and \ b = -5, \ (a - b)/(a + b) + a -b = 0

(d) When a = 4 and b = -5, (a + b)² - (a - b)² = 82

Explanation:

The question relates to evaluation of expressions, given the values of the variables, "a" and "b"

Where;

a = 4 and b = -5

(a) For a² + b² - a·b, we have;

a² + b² - a·b = 4² + (-5)² - 4 × (-5) = 16 + 25 + 20 = 41 + 20 = 61

(b) For a³·b + a·b² we have;

a³·b + a·b² = 4³·(-5) + 4·(-5)² = 64 × (-5) + 4 × 25 = -320 + 100 = -220

(c) For
(a - b)/(a + b) + a -b, we have;


(a - b)/(a + b) + a -b = (4 - (-5))/(4 + (-5)) + 4 - (-5) = (4 + 5)/(4 -5) + 4 + 5= (9)/(-1) + 4 + 5 = -9 + 4 + 5 = 0


\therefore when \ a = 4 \ and \ b = -5, \ (a - b)/(a + b) + a -b = 0

(d) For (a + b)² - (a - b)² we have;

(a + b)² - (a - b)² = (4 + (-5))² - (4 - (-5))² = (4 - 5)² - (4 + 5)² = (-1)² - 9² = 1 + 81 = 82

When a = 4 and b = -5, (a + b)² - (a - b)² = 82

User Lukasz Szczygielek
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories