Question

If 31.5 grams of hydrogen peroxide reacts to form 16.7 grams of water, how many grams of oxygen must simultaneously be formed?

Answer 1

Consider the reaction:

2 H₂O₂ =>2 H₂O + O₂

2 moles of H₂O₂ will give=2 moles of H₂O and 1 mole of O₂

1 moles of H₂O₂ will give=1 moles of H₂O and 0.5 mole of O₂

31.5 g of H₂O₂=

`(31.5)/(34.017)(g)/(mol)`

=
`0.0924 {g}{mol}`

0.0924 moles of H₂O₂ will give= 0.5 × 0.0924 mole of O₂

=0.462 mole of O₂

0.462 mole of O₂×32 g/mol

14.784 g of O₂

If 31.5 grams of hydrogen peroxide reacts to form 16.7 grams of water, 14.784 g of oxygen must simultaneously be formed