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Consider the graph of the linear function h(x) = -6 + 2/3 x. Which quadrant will the graph not go through and why.

User Eggbert
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2 Answers

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There are four quadrants.

I. x>0, y>0

II. x<0, y>0

III. x<0, y<0

IV. x>0, y<0

note that for any x<0, h(x) < 0 (that corresponds to III)

Why?
(2/3)x <0\\\therefore (2/3)x - 6 < 0

So, the graph not go through II.

Note that, if x = 3, h(3) = -4 < 0, (that corresponds to IV), and if x = 12, h(12) = 2> 0, that corresponds to I.


User Resa
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1 vote

Answer:

The answer is b guys

Explanation:

User Luek Baja
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