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The ratio of hydrogen to oxygen atoms in water molecules is 2 to 1. If the beaker of water contained 4.1 moles of oxygen atoms, how many moles of hydrogen atoms did it contain?

(Note: A mole is a unit commonly used in chemistry. You don't need to know this to solve the problem, but in case you are interested, 1 mole=6.02 times 10^23 atoms)

PLZ HELP!!!!!!!!!!!

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2 votes

Answer:

8.2

Step-by-step explanation:

We have been given that the ratio of hydrogen to oxygen atoms in water molecules is 2 to 1.

We can represent this information as:
\frac{\text{Hydrogen}}{\text{Oxygen}} =(2)/(1)

Let x be amount of moles of hydrogen atoms in water beaker. The proportion of hydrogen and oxygen moles will be same in water beaker.

Upon substituting our values in above proportion we will get,


(2)/(1) =(x)/(4.1)


x=2* 4.1


x=8.2

Therefore, the moles of hydrogen atoms in water beaker will be 8.2.

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