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What is the apparent weight of this same object at the neptune's equator? (note that neptune's "surface" is gaseous, not solid, so it is impossible to stand …

What is the apparent weight of this same object at the neptune's equator? (note that neptune's "surface" is gaseous, not solid, so it is impossible to stand …
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What is the apparent weight of this same object at the neptune's equator? (note that neptune's "surface" is gaseous, not solid, so it is impossible to stand on it.)?

User Cosmo D
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Since weight reflects the Normal Force of a surface to an object due to gravitational acceleration, if there is no physical surface to provide the Normal Force, the apparent weight would be 0N.
User Alex Pacurar
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