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If the mEF = 60° and the diameter of this circle is 16 inches, what is the arc length of EF?

(Write your answer to the nearest hundredth.)

1 Answer

5 votes

Answer:

8.38 inches (rounded up to the nearest hundredth)

Explanation:

mEF = 60°

Diameter = 16 inches

Arc length EF is given by:

EF =
(mEF)/(360) × 2πr

Radius = 16 inches ÷ 2 = 8 inches

EF =
(60)/(360) × 2π(8)

EF = 8.38 inches (rounded up to the nearest hundredth)


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