Answer:
O₂
Explanation:
You decompose KClO₃ in the lab to prepare oxygen according to the equation
2KClO₃ ⟶ 2KCl + 3O₂
K and Li are Group 1 metals, so LiClO₃ should have properties like those of KClO₃.
It should decompose to form oxygen.
2LiClO₃ ⟶ 2LiCl + 3O₂