Triangle FCE congruent to Triangle FDE by HL. I thought at first that it was answer 2, but after further study it is answer 1
Answer:
ΔFCE≅ΔFDE
Explanation:
Given: CF=DF
In ΔFCE and ΔFDE,
CF=DF (Given)
∠CFE=∠DFE (Equal sides have equal angles)
FE=FE (common)
Therefore, by SAS rule of congruency,
ΔFCE≅ΔFDE,
⇒∠1=∠2
Hence option A is used in solving the problem.
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