Question

GEOMETRY: Help ASAP! Show all work. Incomplete or off-topic answers will be reported.

37. M is the midpont of line jk. find the coordinates of k.

J(0,11), M(-3,2)

40. Find the circumference and area for each circle in terms of pi.

r = 3 in.

Answer 1

midpoint of (x1,y1) and (x2,y2) is
`((x_1+x_2)/(2), (y_1+y_2)/(2)`

so if midpoint is (-3,2) and one point is (0,11) then

`(-3,2)=((0+x_2)/(2), (11+y_2)/(2))`

`-3=(x_2)/(2)`

`-6=x_2`

`2=(11+y_2)/(2)`

`4=11+y_2`

`-7=y_2`

the coordinates of k is (-6,-7)

circumference=2*pi*r

area=pi*r^2

if r=3 then

circumference=2*pi*3=6pi in

area=pi*3^2=pi*3*3=9pi in²