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Sally spins a fair spinner numbered 1 - 5 and rolls a fair dice.

What is the probability of obtaining a multiple of 3 and a factor of 10?

User Jryl
by
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1 Answer

5 votes

Answer: Probability of obtaining a multiple of 3 and a factor of 10 is given by


(1)/(10)

Explanation:

Since we have given that

There is a fair spinner numbered 1-5 and a fair dice

Total number of outcomes of fair spinner = 5

Total number of outcomes of a fair dice = 6

Let Event A: Getting a multiple of 3 on a spinner

Event B: Getting a factor of 10 on a fair dice

The possible outcomes of multiple of 3 on a spinner is


3

The possible outcomes of factor of 10 on a fair dice are


1,2,5

So,


P(A)=(1)/(5)

and


P(B)=(3)/(6)=(1)/(2)

Since A and B are independent events so,


P(A\ and\ B)=P(A).P(B)\\\\P(A\ and\ B)=(1)/(5)* (1)/(2)\\\\P(A\ and\ B)=(1)/(10)

Hence, Probability of obtaining a multiple of 3 and a factor of 10 is given by


(1)/(10)


User Noeldiaz
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8.2k points