Question

Sally spins a fair spinner numbered 1 - 5 and rolls a fair dice.

What is the probability of obtaining a multiple of 3 and a factor of 10?

Answer 1

Answer: Probability of obtaining a multiple of 3 and a factor of 10 is given by

`(1)/(10)`

Explanation:

Since we have given that

There is a fair spinner numbered 1-5 and a fair dice

Total number of outcomes of fair spinner = 5

Total number of outcomes of a fair dice = 6

Let Event A: Getting a multiple of 3 on a spinner

Event B: Getting a factor of 10 on a fair dice

The possible outcomes of multiple of 3 on a spinner is

`3`

The possible outcomes of factor of 10 on a fair dice are

`1,2,5`

So,

`P(A)=(1)/(5)`

and

`P(B)=(3)/(6)=(1)/(2)`

Since A and B are independent events so,

`P(A\ and\ B)=P(A).P(B)\\\\P(A\ and\ B)=(1)/(5)* (1)/(2)\\\\P(A\ and\ B)=(1)/(10)`

Hence, Probability of obtaining a multiple of 3 and a factor of 10 is given by

`(1)/(10)`