Question

PLEASE HELP!!!!!!!

In 2000, the population of a town was 8914. The population is expected to grow at a rate of 1.36% each year. What is the population of the town in 2006? Round the answer to the nearest whole number.

Answer 1

Answer: 9667

Step-by-step explanation: took the test

Answer 2

9667

Explanation:

The population is 8914 in 2000. We must exlude the growth in 2000. Therefore, the population grows for 6 years. We can write an expression for the population growth. The growth rate applies to the total population of the previous year. So for year 2001 the population will be:

`=(8914*0.0136)+8914=9035.23`

So for 2002 we will take 2001 population and multiply it by the growth rate and add 2001 population to get 2002 total population:

`=(9035.23*0.0136)+9035.23=9158.11`

For 2003:

`=(9158.11*0.0136)+9158.11=9282.66`

For 2004:

`=(9282.66*0.0136)+9282.66=9408.9`

For 2005:

`=(9408.9*0.0136)+9408.9=9536.85`

For 2006:

`=(9536.85*0.0136)+9536.85=9666.55`

The population in 2006 is 9667