Question

A 3.0 N force and a 5.0 N force are acting in opposite directions on the same 5.0 kg ball. What is the magnitude of the acceleration of the ball?

Answer 1

F(net)=ma

(5-3)=5a
2=5a
a=0.4

Hope I can help u

Answer 2

The acceleration of the ball is
`0.4\ m/s^2`

Step-by-step explanation:

It is given that,

Force acting on the object, F₁ = 3 N (right side)

Force acting on the object, F₂ = 5 N (left side)

Mass of the ball, m = 5 kg

We need to magnitude of the acceleration of the ball. First of all, we need to find the net force acting on the ball.

`F_(net)=F_2-F_1`

`F_(net)=5-3=2\ N`

Now let a is the acceleration of the ball. It can be calculated using second law of motion as :

`a=\frac{F{net}}{m}`

`a=(2\ N)/(5\ kg)`

`a=0.4\ m/s^2`

So, the acceleration of the ball is
`0.4\ m/s^2`. Hence, this is the required solution.