Answer:
NO(g) + 2H2O(l) + 3Ag^+(aq)---------> NO3^-(aq) + 4H^+(aq) + 3Ag
Step-by-step explanation:
Oxidation half equation
NO(g) + 2H2O(l)--------> NO3^-(aq) + 4H^+(aq). + 3e
Reduction half equation
3Ag^+(aq) + 3e--------> 3Ag
Overall reaction equation
NO(g) + 2H2O(l) + 3Ag^+(aq)---------> NO3^-(aq) + 4H^+(aq) + 3Ag