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The function y= sin 3x with the interval 0 < x < 2pi has how many cycles in 2pi ?

A. 6
B. 1
C. 3
D. 1.5

And please explain!

1 Answer

4 votes

Answer:

C is correct. 3 cycles will complete in 0 to 2π

Explanation:

We are given function y=sin 3x with interval
0\leq x\leq 2\pi

As we know the period of y=sin x is 2π

It means in 0 to 2π sin x complete one cycle.

But here we have y=sin(3x) So, period of this function should be different.

Here coefficient of x is 3.

So, In interval 0 to 2π. Total number of cycles would be 3.

Thus, 3 cycles will complete in 0 to 2π

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