Question

PLEASE HELP - precalc

Answer 1

1, 8/7

Explanation:

`f \circ g=(1)/((1)/(x-1)-7)`

We know the domain excludes the values that make the denominator of a fraction equal 0.

From this, we know that:

`x-1 \\eq 0 \implies \boxed{x \\eq 1} \\ \\ (1)/(x-1)-7 \\eq 0 \\ \\ (1)/(x-1) \\eq 7 \\ \\ 1 \\eq 7x-7 \\ \\ 8 \\eq 7x \\ \\ \boxed{x \\eq 8/7} \\ \\ \therefore a=1, b=8/7`