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42 votes
42 votes
Calculate the acceleration for a 103 kg box, if the horizontal force is 370 N and the friction force is 123 N.

User Luis Lobo
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1 Answer

28 votes
28 votes

Answer:

a ≈ 2.4 m/s²

Step-by-step explanation:

Given:

m = 103 kg

F₁ = 370 N

F₂ = 123 N

___________

a -?

According to Newton 's Second law:

m·a = F₁ - F₂

Acceleration:

a = (F₁ - F₂) / m

a = (370 - 123) / 103 ≈ 2.4 m/s²

User BoxOfNotGoodery
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3.1k points