Question

Find the midpoint of the line segment whose endpoints are given (3/5 , -6/7),(2/5,5/7)

Answer 1

The formula of a midpoint between E and F:

`M_(EF)\left((x_E+x_F)/(2);\ (y_E+y_F)/(2)\right)`

We have the points
`\left((3)/(5),\ -(6)/(7)\right)` and
`\left((2)/(5),\ (5)/(7)\right)`. Substitute:

`((3)/(5)+(2)/(5))/(2)=((5)/(5))/(2)=(1)/(2)\\\\(-(6)/(7)+(5)/(7))/(2)=(-(1)/(7))/(2)=-(1)/(7)\cdot(1)/(2)=-(1)/(14)`

Answer:
`\boxed{\left((1)/(2),\ -(1)/(14)\right)}`