Question

If 2.4 grams of O2 react with excess CH4, how many grams of CO2 result?

CH4 (g) +202(g) ->CO2(g) + 2H₂O(1)

Answer 1

1.65g

Step-by-step explanation:

2 moles of O₂ gives 1 mole of CO₂

1 mole of O₂ = 32g

2 moles of O₂ = 64g

(Note that O₂ is the limiting reagent. It is in less quantity as compared to CH₄. The resultant product of CO₂ formed is proportional to that of the amt. of O₂. Some amt. of CH₄ will remain after reaction.)

1 mole of CO₂ = 44g

Therefore, 2.4 g of O₂ gives 'x' g of CO₂

⇒ x = 44 * 2.4/64 = 6.6/4 = 3.3/2 = 1.65g

ANSWER : 1.65 g of CO₂ forms as product