Answer:
Perimeter = 32 cm
Explanation:
Use the property of tangents drawn to a circle,
"Length of tangents drawn to a circle drawn from a point given outside the circle are equal"
AE = AH = 3 cm
BE = FB = 4 cm
CG = CF = 5 cm
Since, ∠B ≅ ∠D,
Therefore, length of tangents drawn from D will be equal to the length of tangents drawn form B.
Therefore, DG = DH = 4 cm
Now AB = AE + BE
= 3 + 4
= 7 cm
BC = FB + CF
= 4 + 5
= 9 cm
CD = CG + DG
= 5 + 4
= 9 cm
AD = AH + HD
= 3 + 4
= 7 cm
Perimeter of ABCD = AB + BC + CD + AD
= 7 + 9 + 9 + 7
= 32 cm