Answer:
x+2 < 11 and -x-2 < 11
Explanation:
absolute value function has two solution
|x| = a
Then x=a and - x= a
|x + 2| < 11
Then x + 2 < 11 and -(x + 2) < 11
x + 2 < 11 and -x - 2 < 11
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