Question

Assume a quarter, diameter 0.96 inches, is centered at the point (–2, 5), where each unit represents one inch. Write the equation of a circle that would precisely enclose the coin.

Answer 1

`(x+2)^(2)+(y-5)^(2)=0.2304`

Explanation:

we know that

The equation of a circle into center radius form is equal to

`(x-h)^(2)+(y-k)^(2)=r^(2)`

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem we have

`r=Diameter/2=0.96/2=0.48\ in`

`(h,k)=(-2,5)`

substitute

`(x+2)^(2)+(y-5)^(2)=0.48^(2)`

`(x+2)^(2)+(y-5)^(2)=0.2304`