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A ball is projected with velocity 10m/s at an angle of 30 degrees with the horizontal surface . The time taken by the ball to reach the ground is ... g=10

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The ball's vertical position in the air is given by


y=10\cos30^\circ\,t-\fracg2t^2

and it will reach the ground at
t for which
y=0:


0=5\sqrt3\,t-5t^2=5t(\sqrt 3-t)\implies t=\sqrt3\approx1.73

User Will Charczuk
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