Question

Given the center (h,k) = (5,0) and radius r=3, write and equation for the circle in standard form

Answer 1

B. it is (x-5)^2+y^2=9

Answer 2

B)
`(x-5)^(2) + y^(2) = 9`

Step by step explanation

The standard form of circle when center(h, k) and radius r, given is

(x - h)^2 + (y - k)^2 = r^2

Given: (h, k) = (5, 0) and r = 3

Now plug in these values in the standard form, we get

(x - 5)^2 + (y - 0)^2 = 3^2

`(x- 5)^(2) + y^(2) = 9`

Therefore, the answer is B)
`(x-5)^(2)  + y^(2) = 9`

Thank you :)