Question

What is the point-slope form of the equation"parallel to the line y=3/5x -8; passes through (0,-3)"

Answer 1

The point-slope form of the equation for the parallel line is , which utilizes the slope <\frac{3}{5}> from the given line and the point <(0,-3)> through which the new line passes.

Step-by-step explanation:

The point-slope form of the equation for a line parallel to y=\frac{3}{5}x-8 and passing through the point (0,-3) can be determined using the given slope and point. Since parallel lines have the same slope, the slope of our line will also be \frac{3}{5}. The point-slope form of an equation can be written as (y-y_1)=m(x-x_1), where m is the slope and (x_1, y_1) is a point the line passes through.

Substituting the given slope and point into the point-slope formula, we get (y+3)=\frac{3}{5}(x-0) or (y+3)=\frac{3}{5}x. Therefore, the point-slope form for the line that is parallel to the given line and passes through the point (0, -3) is (y+3)=\frac{3}{5}x.

Answer 2

The equation of that line would be y = 3/5x - 3

Step-by-step explanation:

In order to find this line, we need to find note that the slope would be the same as the original line (since parallel lines have the same slope). Now we can use that and the point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - -3 = 3/5(x - 0)

y + 3 = 3/5x

y = 3/5x - 3