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If a line started at the point (-2,6) and has a slope of 3, what is the equation of the line?

User Amod
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1 Answer

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The slope-intercept form:


y=mx+b

We have the point (-2, 6) and the slope m = 3. Substitute:


6=3(-2)+b


6=-6+b add 6 to both sides


12=b\to b=12

Answer:
\boxed{y=3x+12}

User Fernando Urkijo
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