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Line AB passes through points A(–6, 6) and B(12, 3). If the equation of the line is written in slope-intercept form, y = mx + b, then m = – and b = .

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The formula of a slope:


m=(y_2-y_1)/(x_2-x_1)

We have the points A(-6, 6) and B(12, 3). Substitute:


m=(3-6)/(12-(-6))=(-3)/(18)=-(3:3)/(18:3)=-(1)/(6)

Therefore we have
y=-(1)/(6)x+b.

Put the coordinates of the point B to the equation:


3=-(1)/(6)(12)+b


3=-2+b add 2 to both sides


5=b\to b=5

Answer:


m=-(1)/(6)\\\\b=5

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