Question

What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?What are the solutions of this equation? 47 m 2 + 88 m + 39 = 0

Answer 1

x= 5+√31/2, 5-√31/2

and

m= -44±√103/47

m≈ -0.72023634, -1.15210407

Answer 2

Hi!

For f(x) = 2x^2 – 10x – 3, the zeros for this quadratic are:

• 
  `x_1 = -(5)/(2) + (√(31))/(2) \approx 5.28`

• 
  `x_2 = (5)/(2) - (√(31))/(2) \approx -0.28`

For f(m) = 47m^2 – 88m + 33 = 0, the solutions for this equation are:

• 
  `m_1 = -(44)/(47) - (√(103))/(47) \approx -1.15`

• 
  `m_2 = -(44)/(47) + (√(103))/(47) \approx -0.72`

Explanation:

Having a quadratic function: ax^2 + bx + c = 0, the values of x which are the solutions of the equation are given by the quadratic formula.

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