Question

Write an equation of a line in slope intercept form to the given line and pass through the given point

y = 4x + 6 ; (4,8)

I'm not sure as to how to start or what steps to use

Answer 1

Slope intercept form is:

y = mx + b

"m" is the slope, "b" is the y-intercept (when x = 0)

I'm assuming that the equation of a line is parallel to the given line.

When lines are parallel, they have the same slope.

The given line's slope is 4, so the parallel line's slope is also 4

y = mx + b

y = 4x + b

To find b, you plug in the point (4,8) into the equation.

y = 4x + b

8 = 4(4) + b

8 = 16 + b Subtract 16 on both sides

-8 = b

Your equation is:

y = 4x - 8

Answer 2

okay so the equation given to you, tells you that the slope must be 4. The line must pass through the point (4,8). so, you have to put it into point-slope form in order to find your answer. the equation for point slope form is y-y1 =m(x-x1). in the equation, y1 and x1 are given in the point (4,8), so you point slope equation will be y-8=4(x-4). then you solve the equation. hope this helps! :)