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Use approximation to tell which fraction is greater 10/21 and 15/28

1 Answer

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Consider two fractions
(10)/(21) and
(15)/(28).

1. Approximate first fraction by
(10)/(20). You know that


(10)/(20)=(1)/(2) and comparing two fractions with the same numerators, we compare their denominators. Since
21>20, then


(10)/(21)<(10)/(20),\\ \\(10)/(21)<(1)/(2).

2. Approximate the second fraction by
(14)/(28). You know that


(14)/(28)=(1)/(2) and comparing two fractions with the same denominators, we compare their numerators. Since
15>14, then


(15)/(28)>(14)/(28),\\ \\(15)/(28)>(1)/(2).

You have two fractions, the first one is less than
(1)/(2) and the second one is greater than
(1)/(2). Thus,


(10)/(21)<(15)/(28).

Answer:
(10)/(21)<(15)/(28).

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