Question

If the current in this circuit is 3 A, what must be the value of R3?


It's 5 Ω

Answer 1

5

Step-by-step explanation:

Answer 2

Explanation :

It is given that,

In the given figure all the three resistors are in series.

Current flowing in the circuit,
`I=3\ A`

Voltage,
`V=30\ V`

We know that in series circuit the current flowing in all resistors is same.

Using Ohm's law, we get:

`V=IR`

`30\ V=3\ A(2\ \Omega+3\ \Omega+R_3)`

`R_3=5\ \Omega`

Hence, this is the required solution.