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Help please I get y=mx+b but I'm not sure how to do this

Help please I get y=mx+b but I'm not sure how to do this-example-1
User Squishy
by
9.1k points

2 Answers

1 vote

y =
(1)/(2) x +
(5)/(2)

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (3, 4 ) and (x₂, y₂ ) = (9, 7 )

m =
(7-4)/(9-3) =
(3)/(6) =
(1)/(2)

y =
(1)/(2) x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (3, 4 ) then

4 =
(3)/(2) + c ⇒ c =
(5)/(2)

y =
(1)/(2) x +
(5)/(2) ← equation in slope-intercept form




User John Sparwasser
by
8.1k points
5 votes

(3,4) (9,7)

to find the slope

m = (y2-y1)/(x2-x1)

= (7-4)/(9-3)

3/6

1/2

The slope is 1/2

point slope form

y-y1 = m(x-x1)

y-4 = 1/2(x-3)

distribute

y-4 = 1/2x -3/2

add 4 to each side

y = 1/2 x -3/2 + 4

y = 1/2 x -3/2 + 8/2

y = 1/2 x + 5/2

this is in slope intercept form

User Michalh
by
8.3k points

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