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An 8.50 L tire contains .552 lol of gas at a temperature of 305 K. What's the pressure , in atm and in psi, of the gas in the tire?
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An 8.50 L tire contains .552 lol of gas at a temperature of 305 K. What's the pressure , in atm and in psi, of the gas in the tire?

User Bhavesh Hirpara
by
8.6k points

1 Answer

6 votes
PV=nRT
P×8.5=0.552×0.082×305
8.5P=13,80552

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User Andreas Linden
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